Find the sum of each arithmetic series \sum_{p=4}^{11}\left(2p+

leviattan0pi

leviattan0pi

Answered question

2021-11-16

Find the sum of each arithmetic series
p=411(2p+1).

Answer & Explanation

breisgaoyz

breisgaoyz

Beginner2021-11-17Added 14 answers

Step 1
We have,
p=411(2p+1)
=9+11+13+15+17+..+23
We got,
n=8 (Number of Terms)
a=9 (first term)
Common difference =2
Now,
Sum,
Sn=n2[2a+(n1)d]
=82[2×9+(81)×2]
=4[18+14]
Sn=128
Required Sum of arithmetic series is 128.
Step 2
We have been given the general formula so we will expand it to get the series.
To get the sum we requires first term, number of terms and the common difference between the terms.
Once we have all this we can get the sum easily.
Jeffrey Jordon

Jeffrey Jordon

Expert2022-08-30Added 2605 answers

Answer is given below (on video)

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