(0.1,\ 1.45),\ (0.2,\ 2.20),\ (0.4,\ 3.76) and (0.5,\ 432)

miyoko23q3

miyoko23q3

Answered question

2021-11-18

(0.1, 1.45), (0.2, 2.20), (0.4, 3.76) and (0.5, 432) datas are given. P(0) is approximated using Neville's Method as an approximation of (0). So compute the sum Q3.7+Q2.2+P(0). (Use 5 digs rounding arithmetic)
A.4.2569
B.4.4232
C.4.1509
D.4.0534

Answer & Explanation

Mike Henson

Mike Henson

Beginner2021-11-19Added 11 answers

Given data,
The table of the data is,
xf(x)0.11.450.22.200.43.760.54.32
Step 1
The Q notation table is,
x0p0=Q0.0x1p1=Q1.0p1.1=Q1.1x2p2Q2.0p1.2=Q2.1p0.1.2=Q2.2x33.76p2.3=Q3.1p1.2.3Q3.2x44.32p3.4=Q4.1p2.3.4
Step 2
Calculating the first degree approximation,
Q3.1=(xx2)Q3.0(xx3)Q2.0x3x2
=(00.4)4.32(00.5)3.760.50.4
=0.44.32+0.53.760.1
=1.52
Q2.2=(xx1)Q2.1(xx2)Q1.1x2x1
=(00.2)0.64(00.4)1.70.40.2
=0.20.64+0.41.70.2
=2.76
Step 3
The value of f (0) is 0.1432.
The sum of Q3.1+Q2.2+P(O)is,
Q3.1Q2.2+P(O)=1.52+2.76+0.1432
=4.4232
Hence option Bis correct.

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