Solve quadratic equation. 9x^{2}+6x+1=0

Jason Watson

Jason Watson

Answered question

2021-11-21

Solve quadratic equation.
9x2+6x+1=0

Answer & Explanation

Mespirst

Mespirst

Beginner2021-11-22Added 17 answers

Step 1
Consider the given equation.
9x2+6x+1=0
Now, find the factor of the equation.
9x2+6x+1=0
9x2+3x+3x+1=0
3x(3x+1)+1(3x+1)=0
(3x+1)2=0
Step 2
Further simplify.
(3x+1)=0
3x=-1
x=13
Therefore, the solution of the equation is x=13.
Mespirst

Mespirst

Beginner2021-11-23Added 17 answers

Step 1: Use the formula for the roots of the quadratic equation
x=b±b24ac2a
In the standard form, determine a, b and c from the original equation and insert them into the formula for the roots of the quadratic equation.
9x2+6x+1=0
a=9
b=6
c=1
x=6±6249129
Step 2: Raise to the degree
x=6±3649129
x=6±3649129
Step 3: Multiply the numbers
x=6±3649129
x=6±363629
Step 4: Subtract the numbers
x=6±363629
x=6±029
Step 5: Calculate the square root
x=6±029
x=6±029
Step 6: Add zero
x=6±029
x=629
Step 7: Multiply the numbers
x=629
x=618
Step 8: Reduce the same terms in the numerator and denominator
x=618
x=13
The solution
x=13

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?