Lorraine Harvey
2021-12-12
vicki331g8
Beginner2021-12-13Added 37 answers
Step 1
In this case, a polynomial function of 3 with the zeros 3i and 9/5 is written.
Step 2
Let f(x) be the ploynomial function
Given that 3i are the zeros of f(x), +3i are the zeros of f. (x)
[because complex conjugate each other]
Since −3i be the zeros of f(x) then (x+3i) be the factor of f(x).
Since +3i be the zeros of f(x) then (x−3i) be tge factor of f(x)
Since 9/5 be the zeros of f(x) , then (x−9/5) be the factor of f(x).
Step 3
Therefore f(x)=(x+3i)(x−3i)(x−9/6)
Hence
Nadine Salcido
Beginner2021-12-14Added 34 answers
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