veksetz

2021-12-15

How do you solve for x in $ax-c=b$ ?

Raymond Foley

Beginner2021-12-16Added 39 answers

First, add c to each side of the equation to isolate the x term while keeping the equation balanced:

$ax-c+c=b+c$

$ax-0=b+c$

$ax=b+c$

Now, divide each side of the equation by a to solve for x while keeping the equation balanced:

$\frac{ax}{a}=\frac{b+c}{a}$

$\frac{ax}{a}=\frac{b+c}{a}$

$x=\frac{b+c}{a}$

Or

$x=\frac{b}{a}+\frac{c}{a}$

Now, divide each side of the equation by a to solve for x while keeping the equation balanced:

Or

Melissa Moore

Beginner2021-12-17Added 32 answers

Add c in both sides, we get ax - c + c = b + c

$\Rightarrow ax=b+c$

$\Rightarrow \frac{ax}{a}=\frac{b+c}{a}$

$\Rightarrow x=\frac{b+c}{a}$

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