Pam Stokes

2021-12-15

Multiply the polynomials using the special product formulas.

$(3x-2)}^{3$

hysgubwyri3

Beginner2021-12-16Added 43 answers

Step 1

Multiply the polynomials using the special product formulas.

$(3x-2)}^{2$

Step 2

Now,$(3x-2)}^{3$

$={\left(3x\right)}^{3}-3\cdot {\left(3x\right)}^{2}+3\cdot 3x\cdot {2}^{2}-{2}^{3}$

$(\because {(a-b)}^{3}={a}^{3}-3{a}^{2}b+3a{b}^{2}-{b}^{3})$

$=27{x}^{3}-3\left(9{x}^{2}\right)\cdot 2+9x\cdot 4-8$

$=27{x}^{3}-54{x}^{2}+36x-8$

$\therefore {(3x-2)}^{3}=27{x}^{3}-54{x}^{2}+36x-8$

Multiply the polynomials using the special product formulas.

Step 2

Now,

$\frac{20b}{{\left(4{b}^{3}\right)}^{3}}$

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