Solve the following differential equation by factorization method. x^{2}-2ax+a^{2}-b^{2}=0

lugreget9

lugreget9

Answered question

2021-12-18

Solve the following differential equation by factorization method.
x22ax+a2b2=0

Answer & Explanation

Piosellisf

Piosellisf

Beginner2021-12-19Added 40 answers

Step 1
The given quadratic equation is, x22ax+a2b2=0
Step 2
2a is written as, 2a=(a+b)+(a-b) and a2b2=(a+b)(ab)
x2((a+b)+(ab))x+(a+b)(ab)=0
x2(a+b)x(ab)x+(a+b)(ab)=0
x(x-(a+b))-(a-b)(x-(a+b))
(x-(a+b))(x-(a-b))
x-(a+b)=0, x-(a-b)=0
x=(a+b), x=(a-b)
x=a+b, x=a-b
This is the solution of the quadratic equation is, x22ax+a2b2=0
Louis Page

Louis Page

Beginner2021-12-20Added 34 answers

Step 1
Given quadratic equation is x22ax+a2b2=0
Factorizing the given equation is
x2(a+b)x(ab)x+a2b2=0
x(x-(a+b))-(a-b)(x-(a+b))=0
(x-(a+b))(x-(a-b))=0
x=(a+b), (a-b)
Step 2
Hence obtained

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?