Jason Yuhas

2021-12-19

Choose the prime factorization of 120.

A)${2}^{2}\cdot 3\cdot 10$

B)${2}^{3}\cdot 3\cdot 5$

C)10*12

D)2*5*12

A)

B)

C)10*12

D)2*5*12

sonSnubsreose6v

Beginner2021-12-20Added 21 answers

Step 1

to find prime factorization

Start by dividing the number by the first prime number 2 and continue dividing by 2 until you get a decimal or remainder. Then divide by 3, 5, 7, etc. until the only numbers left are prime numbers.

Step 2

$120=2\times 2\times 2\times 3\times 5$

prime factorization of 120

${2}^{3}\times 3\times 5$

Step 3

Answer B

to find prime factorization

Start by dividing the number by the first prime number 2 and continue dividing by 2 until you get a decimal or remainder. Then divide by 3, 5, 7, etc. until the only numbers left are prime numbers.

Step 2

prime factorization of 120

Step 3

Answer B

Bertha Jordan

Beginner2021-12-21Added 37 answers

Step 1

As we know,

Prime factorization is a process of factoring a number in term of prime number.

Step 2

Now,

$\therefore 120$

$\Rightarrow \frac{120}{2}=60$

$\Rightarrow \frac{60}{2}=30$

$\Rightarrow \frac{30}{2}=15$

$\Rightarrow \frac{15}{3}=5$

5 is prime number

Hence, prime factor of 120 is

=2*2*2*3*5

$={2}^{3}\cdot 3\cdot 5$

$\therefore$ Prime factorization of 120 is ${2}^{3}\cdot 3\cdot 5$ .

As we know,

Prime factorization is a process of factoring a number in term of prime number.

Step 2

Now,

5 is prime number

Hence, prime factor of 120 is

=2*2*2*3*5

$\frac{20b}{{\left(4{b}^{3}\right)}^{3}}$

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