aramutselv

2021-12-18

Multiply the polynomials using the FOIL method. Express your answer as a single polynomial in standard form.

(x-2y)(x+y)

(x-2y)(x+y)

Corgnatiui

Beginner2021-12-19Added 35 answers

Step 1

Given:

(x-2y)(x+y)

To Find:

Using FOIL method express the polynomial in standard form

Step 2

Explanation:

FOIL(First, Outer, Inner, Last)

So,$(x-2y)(x+y)={x}^{2}+xy-2xy-2{y}^{2}$

$\Rightarrow (x-2y)(x+y)={x}^{2}-xy-2{y}^{2}$

Step 3

Answer:

$(x-2y)(x+y)={x}^{2}-xy-2{y}^{2}$

Given:

(x-2y)(x+y)

To Find:

Using FOIL method express the polynomial in standard form

Step 2

Explanation:

FOIL(First, Outer, Inner, Last)

So,

Step 3

Answer:

scoollato7o

Beginner2021-12-20Added 26 answers

Multiply the binomials using the FOIL method.

(x-2y)(x+y)=x*x+x*y+(-2y)x+(-2y)y

Multiply the monomials using the laws of exponents.

$x\cdot x+x\cdot y+(-2y)x+(-2y)y={x}^{1+1}+xy+(-2xy)+(-2{y}^{2})$

$={x}^{2}+xy-2xy-2{y}^{2}$

Combine the like terms using the distributive property.

$x}^{2}+xy-2xy-2{y}^{2}={x}^{2}+(1-2)xy-2{y}^{2$

$={x}^{2}+(-1)xy-2{y}^{2}$

$={x}^{2}-xy-2{y}^{2}$

Therefore, the result is$x}^{2}-xy-2{y}^{2$ .

(x-2y)(x+y)=x*x+x*y+(-2y)x+(-2y)y

Multiply the monomials using the laws of exponents.

Combine the like terms using the distributive property.

Therefore, the result is

$\frac{20b}{{\left(4{b}^{3}\right)}^{3}}$

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