Multiply the polynomials using the FOIL method. Express your answer

Pam Stokes

Pam Stokes

Answered question

2021-12-18

Multiply the polynomials using the FOIL method. Express your answer as a single polynomial in standard form.
(-2x-3y)(3x+2y)

Answer & Explanation

Melinda McCombs

Melinda McCombs

Beginner2021-12-19Added 38 answers

Step 1
FOIL method is first, outer, inner, last.
The given polynomial is,
(-2x-3y)(3x+2y)
Opening the bracket to solve the equation as,
(2x3y)(3x+2y)=2x×3x2x×2y3y×3x3y×2y
=6x24xy9xy6y2
Step 2
After separating the terms, the final product of the polynomials will be,
(2x3y)(3x+2y)=6x213xy6y2.
vicki331g8

vicki331g8

Beginner2021-12-20Added 37 answers

Multiply the binomials using the FOIL method.
(-2x-3y)(3x+2y)=(-2x)3x+(-2x)2y+(-3y)3x+(-3y)2y
Multiply the monomials using the laws of exponents.
(2x)3x+(2x)2y+(3y)3x+(3y)2y=6x1+1+(4xy)+(9xy)+(6y1+1)
=6x24xy9xy6y2
Combine the like terms using the distributive property.
6x24xy9xy6y2=6x2+(49)xy6y2
=6x2+(13)xy6y2
=6x213xy6y2
Therefore, the result is 6x213xy6y2.

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