Use the difference-of-squares pattern to factor each of the following. x2−64y2

Question

mauricio0815sh · Accepted Answer

Step 1  Given algebraic expression is:  x2−64y2  Both the terms of the above expression are in the form of perfect squares.  Therefore the given algebraic expression follows the difference-of-squares pattern.  Step 2  We use the identity:  a2−b2=(a+b)(a−b)...(1)  Then we get,  x2−64y2  =(x)2−(8y)2  =(x+8y)(x-8y); [using the identity (1)]  Hence is the required factorization.

enlacamig · Accepted Answer

You have to factor the given binomial.
The given binomial is

64 y^{2} - x^{2}

.
The binomial of squares is a binomial of the form

a^{2} - b^{2}

, then its factors will be a+b and a-b.

64 y^{2} - x^{2} = {(8 y)}^{2} - {(x)}^{2}

=(8y+x)(8y-x)
Thus, the factor of the given binomial is

64 y^{2} - x^{2} = (8 y + x) (8 y - x)

.

alenahelenash · Accepted Answer

The given binomial is 64y2−x2. The binomial of squares is a binomial of the form a2−b2, then its factors will be a+b and a-b. 64y2−x2=(8y)2−(x)2 =(8y+x)(8y-x) Thus, the factor of the given binomial is 64y2−x2=(8y+x)(8y−x).

Use the difference-of-squares pattern to factor each of the following.

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