he298c

2021-02-18

Consider the following system of llinear equations.

Part A:

Part B: Write an equivalent system and use elimination method to solve for x and y.

Arnold Odonnell

Skilled2021-02-19Added 109 answers

Step 1: Given,

The linear equations

$\frac{1}{3}x+y=\frac{5}{4}$

$\frac{2}{3}x-\frac{4}{3}y=\frac{5}{3}$

we have to solve these equations by eliminating methods.

Step 2

A.

When multiplying, changing the order of the numbers does not change the product.

B.

Mult. equation (1) by$\frac{4}{3}$ and add both equations, we get

$\frac{4}{9}x+\frac{4}{3}y=\frac{5}{3}$

$\frac{2}{3}x-\frac{4}{3}y=\frac{5}{3}$

we get x=0, put this value in one of the above equation we get

$\frac{1}{3}\times 0+y=\frac{5}{4}$

$y=\frac{5}{4}$

Hence the solution of the given system is (0,$\frac{5}{4}$ ).

The linear equations

we have to solve these equations by eliminating methods.

Step 2

A.

When multiplying, changing the order of the numbers does not change the product.

B.

Mult. equation (1) by

we get x=0, put this value in one of the above equation we get

Hence the solution of the given system is (0,

Jeffrey Jordon

Expert2021-11-08Added 2605 answers

Answer is given below (on video)

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