How do you multiply -3y^{2}-4y+6+2(y^{2}+7y-1)?

kaliitcri

kaliitcri

Answered question

2022-02-06

How do you multiply 3y24y+6+2(y2+7y1)?

Answer & Explanation

venenolundicoofw

venenolundicoofw

Beginner2022-02-07Added 12 answers

Explanation:
Your starting expression is
3y24y+6+2(y2+7y1)
Notice that your expression contains the product between 2 and a paranthesis that features three terms, y2, 7y, and -1.
To expand this paranthesis, multiply each of these terms by 2 to get
2(y2+7y1)=2y2+27y+2(1)=2y2+14y2
Your expression becomes
3y24y+6+2y2+14y2
You can simplify this further by grouping like terms together to get
(3y2+2y2)+(14y4y)+(62)
y2+10y+4

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