How do you FOIL (7x^{7}-9)(x^{8}-9)?

Bryant Miranda

Bryant Miranda

Answered question

2022-02-05

How do you FOIL (7x79)(x89)?

Answer & Explanation

Bordadwayjpf

Bordadwayjpf

Beginner2022-02-06Added 17 answers

Explanation:
FOIL helps you to enumerate all the terms to add when multiplying two binomials.
First: 7x7x8=7x15
Outside: 7x79=63x7
Inside: 9x8=9x8
Last: -9*-9=81
So:
(7x79)(x89)=F+O+I+L
=7x1563x79x8+81
=7x159x863x7+81
using xaxb=xa+b
regresavo552

regresavo552

Beginner2022-02-07Added 14 answers

Explanation:
Have a look:
(7x9)(x89)
=(7x7x8)F+(7x79)O+(9x8)I+(99)L
But xaxb=xa+b
So
=(7x7+8)63x79x8+81=
=7x1563x79x8+81

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