Katelynn Cunningham

2022-02-04

How do you FOIL $(2x-3)({x}^{2}+5x-3)$ ?

Katherine Trevino

Beginner2022-02-05Added 9 answers

This is where FOIL is not quite enough - Its

Pierce Carey

Beginner2022-02-06Added 10 answers

Alternatively, working with each of the powers of x from $x}^{3$ down to $x}^{0$ (i.e. the constant term), match the terms in the first and second bracketed expressions which will multiply to give that power of x and add them together, thus:

Given:$(2x-3)({x}^{2}+5x-3)$

$x}^{3}:2x\times {x}^{2}=2{x}^{3$

$x}^{2}:(2x\times 5x)+(-3\times {x}^{2})=10{x}^{2}-3{x}^{2}=7{x}^{2$

${x}^{1}:(2x\times -3)+(-3\times 5x)=-6x-15x=-21x$

${x}^{0}:-3\times -3=9$

Added, give$2{x}^{3}+7{x}^{2}-21x+9$

Given:

Added, give

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