Expert answers to "How do you find the product 2j(7j2k2+jk2+5k)−9k(−2j2k2+2k2+3j)"

Lyric Morris

Answered question

2022-02-08

How do you find the product

2 j (7 j^{2} k^{2} + j k^{2} + 5 k) - 9 k (- 2 j^{2} k^{2} + 2 k^{2} + 3 j)

tacalaohn

Beginner2022-02-09Added 13 answers

Explanation:
First, eliminate the parenthesis by multiplying each term within the parenthesis by the term outside the parenthesis:

2 j (7 j^{2} k^{2} + j k^{2} + 5 k) - 9 k (- 2 j^{2} k^{2} + 2 k^{2} + 3 j) \Rightarrow

(2 j \times 7 j^{2} k^{2}) + (2 j \times j k^{2}) + (2 j \times 5 k) + (- 9 k \times - 2 j^{2} k^{2}) + (- 9 k \times 2 k^{2})

+ (- 9 k \times 3 j) \Rightarrow

14 j^{3} k^{2} + 2 j^{2} k^{2} + 10 j k + 18 j^{2} k^{3} + (- 18 k^{3}) + (- 27 j k) \Rightarrow

14 j^{3} k^{2} + 2 j^{2} k^{2} + 10 j k + 18 j^{2} k^{3} - 18 k^{3} - 27 j k

Next, group and combine like terms:

14 j^{3} k^{2} + 2 j^{2} k^{2} + 10 j k - 27 j k + 18 j^{2} k^{3} - 18 k^{3}

14 j^{3} k^{2} + 2 j^{2} k^{2} + (10 - 27) j k + 18 j^{2} k^{3} - 18 k^{3}

14 j^{3} k^{2} + 2 j^{2} k^{2} + (- 17) j k + 18 j^{2} k^{3} - 18 k^{3}

14 j^{3} k^{2} + 2 j^{2} k^{2} - 17 j k + 18 j^{2} k^{3} - 18 k^{3}

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