How do you find the product 4n(2n^{3}p^{2}-3np^{2}+5n)+4p(6n^{2}p-2np^{2}+3p)?

uheaeb56e

uheaeb56e

Answered question

2022-02-10

How do you find the product 4n(2n3p23np2+5n)+4p(6n2p2np2+3p)?

Answer & Explanation

Joel Molina

Joel Molina

Beginner2022-02-11Added 9 answers

Explanation:
Simplify
4n(2n3p23np2+5n)+4p(6n2p2np2+3p)
Clear the parentheses by distributing the coefficients
8n4p212n2p2+20n2+24n2p28np3+12p2
There are no like terms, so this is as far as you can go.
You can factor by grouping, but if you do that, there was no point in distributing in the first place.
Maybe you consider this step as a simplification:
Factor out an additional n from the first group, and an additional p from the second group
Simplify
4n2(2n2p23p2+5)+4p2(6n22np+3)
Distributing these coefficients brings back the first answer, which was:
8n4p212n2p2+20n2+24n2p28np3+12p2

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