How do you multiply (3u2−n)2?

Question

tacalaohn · Accepted Answer

Explanation:  (3u2−n)(3u2−n)  9u4−3u2n−3u2n+n2  9u4−6u2+n2

ithangesf4 · Accepted Answer

To expand (3u2−n)2 you can use the FOIL method. That stands for:  Fist  Outer  Inner  Last  In essence, you just want to multiply all combinations of the two brackets.  Since (3u2−n) is squared, you can rewrite (3u2−n)2=(3u2−n)⋅(3u2−n)  Now you use the FOIL method to expand. &quot;First&quot; means you multiply the first term of the first bracket by the first term in the second bracket  3u2⋅3u2=9u4  &quot;Outer&quot; means you multiply the first term in the first bracket by the last term in the second bracket- they are the outermost terms  3u2  ⋅−n=−3ν2  &quot;Inner&quot; means you multiply the second term of the first bracket with the first term in the second bracket  −n⋅3u2=−3ν2  &quot;Last&quot; means you mutiply the last terms of each bracket  −n⋅−n=n2  Now you combine everything:  (3u2−n)2=(3u2−n)⋅(3u2−n)=9u4−3ν2−3ν2+n2=9u4−6ν2+n2

How do you multiply (3u^{2}-n)^{2}?

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