beyondthegametcm

2022-02-11

How do you multiply (8x-5)(4x-7)?

Keely House

Beginner2022-02-12Added 13 answers

Explanation:

each term in the second factor is multiplied by each

term in the first factor

$\Rightarrow (8x-5)\left(4x\right)-7$

=8x(4x-7)-5(4x-7)

$=(8x\times 4x)+(8x\times -7)+(-5\times 4x)+(-5\times -7)$

$=32{x}^{2}+(-56x)+(-20x)+35\leftarrow$ collect like terms

$=32{x}^{2}-56x-20x+35$

$=32{x}^{2}-76x+35$

each term in the second factor is multiplied by each

term in the first factor

=8x(4x-7)-5(4x-7)

Stanley Mcfarland

Beginner2022-02-13Added 17 answers

Given:

(8x-5)(4x-7)

Use the distributive property to distribute the first factor across the second factor:

8x(4x-7)-5(4x-7)

Use the distributive property, again, to multiply through the parentheses:

$32{x}^{2}-56x-20x+35$

Combine like terms:

$32{x}^{2}-76x+35$

This method produces the same results as the F.O.I.L. method but it, unlike the F.O.I.L method, can be used for polynomials of any size.

(8x-5)(4x-7)

Use the distributive property to distribute the first factor across the second factor:

8x(4x-7)-5(4x-7)

Use the distributive property, again, to multiply through the parentheses:

Combine like terms:

This method produces the same results as the F.O.I.L. method but it, unlike the F.O.I.L method, can be used for polynomials of any size.

$\frac{20b}{{\left(4{b}^{3}\right)}^{3}}$

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