How do you find the product of (k+4)(k2+3k−6)?

Question

Layla Humphrey · Accepted Answer

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

(k + 4) (k^{2} - 3 k - 3)

becomes:

(k \times k^{2}) + (k \times 3 k) - (k \times 6) + (4 \times k^{2}) + (4 \times 3 k) - (4 \times 6)

k^{3} + 3 k^{2} - 6 k + 4 k^{2} + 12 k - 24

We can now group and combine like terms:

k^{3} + 3 k^{2} + 4 k^{2} + 12 k - 6 k - 24

k^{3} + (3 + 4) k^{2} + (12 - 6) k - 24

k^{3} + 7 k^{2} + 6 k - 24

losse9x1 · Accepted Answer

Each term in the first bracket must be multiplied by each term in the second bracket. This means there will be 6 terms at first.

(k + 4) (k^{2} + 3 k - 6)

= k (k^{2} + 3 k - 6) + 4 (k^{2} + 3 k - 6)

= k^{3} + 3 k^{2} - 6 k + 4 k^{2} + 12 k - 24

Now add any like terms:

= k^{3} + 7 k^{2} + 6 k - 24

How do you find the product of (k+4)(k^{2}+3k-6)?