ddaeeric

2021-01-10

Perform the indicated divisions of polynomials by monomials.

$\frac{-18{x}^{2}{y}^{2}+24{x}^{3}{y}^{2}-48{x}^{2}{y}^{3}}{6xy}$

crocolylec

Skilled2021-01-11Added 100 answers

A polynomial is an expression of one or more algebraic terms each of which consists of a constant multiplied by one or more variables raised to a non-negative integral power.

Here the given polynomial is a trinomial.

To divide a polynomial by monomial, divide each term of the polynomial by the monomial.

Divide the trinomial by the monomial 6xy.

Simplify the terms which are under division.

Calculation:

Consider the polynomial$\frac{-18{x}^{2}{y}^{2}+24{x}^{3}{y}^{2}-48{x}^{2}{y}^{3}}{6xy}$ .

Divide each term of the polynomial by the monomial 6xy.

$\frac{-18{x}^{2}{y}^{2}+24{x}^{3}{y}^{2}-48{x}^{2}{y}^{3}}{6xy}=(\frac{-18{x}^{2}{y}^{2}}{6xy})+(\frac{24{x}^{3}{y}^{2}}{6xy})+(\frac{-48{x}^{2}{y}^{3}}{6xy})$

$(\frac{-18{x}^{2}{y}^{2}}{6xy})+(\frac{24{x}^{3}{y}^{2}}{6xy})+(\frac{-48{x}^{2}{y}^{3}}{6xy})=-3xy+4{x}^{2}y-8x{y}^{2}$

The simplified value of the polynomial is$-3xy+4{x}^{2}y-8x{y}^{2}$ .

Final statement:

The simplified value of the polynomial after division is equals to$-3xy+4{x}^{2}y-8x{y}^{2}$ .

Here the given polynomial is a trinomial.

To divide a polynomial by monomial, divide each term of the polynomial by the monomial.

Divide the trinomial by the monomial 6xy.

Simplify the terms which are under division.

Calculation:

Consider the polynomial

Divide each term of the polynomial by the monomial 6xy.

The simplified value of the polynomial is

Final statement:

The simplified value of the polynomial after division is equals to

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