Harken43
2022-02-17
Cicolinif73
Beginner2022-02-18Added 7 answers
To see how it arises, first note that in a rational function of degree N in the numerator and degree M in the denominator,
where a 1 has been taken out of the sum in the denominator to eliminate a redundancy in the coefficients, there are M+N+1 free parameters:
It seems natural that this would uniquely specify what R must be, and indeed it does.
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