Yet another logarithm multiplication doubt I'm here again, now with a doubt on multiplication on

e3r6a2n1dz60

e3r6a2n1dz60

Answered question

2022-03-06

Yet another logarithm multiplication doubt
I'm here again, now with a doubt on multiplication on logarithms, I have the expression: (log52+log53log34)log25
I've evaluated it to:
(log56log54log53)1log52
What should I do with this multiplications ?
EDIT: So, I failed miserably on algebra through, so I evaluated now to:
=(log52+log54)log25
=(log58)1log+52
=log5(82)
=log54
So, do I solved it correctly now ? Thank you. EDIT 2:
=(log52+log54)log25
=(log58)1log52
=log58log52
=log28=3

Answer & Explanation

Gianni Martinez

Gianni Martinez

Beginner2022-03-07Added 1 answers

You can't get to that expression. Notice that a+bc(a+b)c What you should do is:
(log52+log53log34)log25=(log52+log53log54log53)1log52
=(log52+log54)1log52=log58log52
=log28=3
You had another mistake: logablogaclogabc
duramadregtw

duramadregtw

Beginner2022-03-08Added 2 answers

You have an algebra error: log52+log53log34log56log34. It should be
(log52+log53log34)log25=(log52+log53log54log53)1log52
=1+log54log52
=1+log522log52
can you finish it from there?

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