How would I evaluate \(\displaystyle{y}={e}^{{{2}{\frac{{{\ln{{2}}}}}{{{3}}}}}}+{e}^{{-{\frac{{{\ln{{2}}}}}{{{3}}}}}}?\)

Nancy Richmond

Nancy Richmond

Answered question

2022-03-30

How would I evaluate
y=e2ln23+eln23?

Answer & Explanation

Avery Maxwell

Avery Maxwell

Beginner2022-03-31Added 13 answers

eln2=2
Use the relation abc=(ab)c, where a=e,b=ln2, and c=23 or 13, so that
y=223+213=213(2+1)=3213

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