Where is the function u <mrow class="MJX-TeXAtom-ORD"> 2

Logan Lamb

Logan Lamb

Answered question

2022-04-04

Where is the function u 2 14 u + 40 ( u 1 ) ( u 2 + 8 u + 15 ) discontinuous?

Answer & Explanation

Braeden Shannon

Braeden Shannon

Beginner2022-04-05Added 13 answers

Simplify (u-1)(u2+8u+15).

u3+7u2+7u-15

Rewrite u2-14u+40(u-1)(u2+8u+15).

u2-14u+40u3+7u2+7u-15

Factor u2-14u+40 using the AC method.

(u10)(u4)u3+7u2+7u15


 

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