Jace Wright

2022-04-04

Where is the function $\frac{{m}^{2}-15m+56}{(m-4)\ufeff({m}^{2}+5m+6)}$ discontinuous?

Taniya Wood

Beginner2022-04-05Added 19 answers

Simplify $(m-4)({m}^{2}+5m+6)$.

${m}^{3}+{m}^{2}-14m-24$

Rewrite $\frac{{m}^{2}-15m+56}{(m-4)({m}^{2}+5m+6)}$.

$\frac{{m}^{2}-15m+56}{{m}^{3}+{m}^{2}-14m-24}$

Factor ${m}^{2}-15m+56$ using the AC method.

$\frac{(m-8)(m-7)}{{m}^{3}+{m}^{2}-14m-24}$

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