What rule is used for this simplification? 8 ( s + 1

junoonib89p4

junoonib89p4

Answered question

2022-05-15

What rule is used for this simplification?
8 ( s + 1 ) 2 + 2 2 × 1 s = 8 5 1 s + 16 10 × s + 1 ( s + 1 ) 2 + 2 2 + 8 10 × 2 ( s + 1 ) 2 + 2 2

Answer & Explanation

hodowlanyb1rq2

hodowlanyb1rq2

Beginner2022-05-16Added 12 answers

Do some partial fraction magic?
8 s ( s 2 + 2 s + 5 ) = A s + B s 2 + 2 s + 5 + C s
This gives C = 8 / 5 , A = 8 / 5 , B = 16 / 5 I think, so
8 s ( s 2 + 2 s + 5 ) = ( 8 5 ) [ 1 s s + 2 s 2 + 2 s + 5 ] .

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