List all the harmonic conjugates of the following rational function. The integration is almost impos

prensistath

prensistath

Answered question

2022-05-20

List all the harmonic conjugates of the following rational function. The integration is almost impossible, Symbolab and Microsoft Math fails to arrive at the answer:
μ ( x , y ) = x 2 + x + y 2 x 2 + y 2

Answer & Explanation

Philip Deleon

Philip Deleon

Beginner2022-05-21Added 4 answers

Look at
(1) μ ( x , y ) = x 2 + x + y 2 x 2 + y 2
in polar coordinates:
(2) μ ( x , y ) = x 2 + x + y 2 x 2 + y 2 = r 2 + r cos θ r 2 = 1 + cos θ r ;
with
(3) z = x + i y = r cos θ + i r sin θ = r e i θ
we have
(4) z 1 = r 1 e i θ = cos θ i sin θ r = cos θ r i sin θ r
is holomorphic on C { 0 }; it follows that, as long as we stay away from r = 0, where μ is not in any event defined, that the harmonic conjugate of cos θ / r is sin θ / r, up to an addidive real constant. In x- y coordinates, we have
(5) sin θ r = r sin θ r 2 = y x 2 + y 2 .
Thus, every harmonic conjugate of μ ( x , y ) is of the form
(6) α y x 2 + y 2 ,
α R a constant, in agreement with the comments of Thomas Andrews.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?