Condense them to the same base before solving for x log16 (x) +log4 (x) +log2 (x) =7

Aneeka Hunt

Aneeka Hunt

Answered question

2020-10-20

Condense them to the same base before solving for x log16(x)+log4(x)+log2(x)=7

Answer & Explanation

Brighton

Brighton

Skilled2020-10-21Added 103 answers

log16(x)=(14)log2(x)
log4(x)=(12)log2(x)
so you hav (1+12+14)log2(x)=7
1.75log2(x)=7
log2(x)=71.75=4
x=24=16

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