Let X,Y be affine varieties, we know that the coordinate ring of the product variety X &#x00D

Case Nixon

Case Nixon

Answered question

2022-05-26

Let X,Y be affine varieties, we know that the coordinate ring of the product variety X × Y satisfies k [ X × Y ] k [ X ] k k [ Y ].
My question is is it true that for rational function field, we also have k ( X × Y ) k ( X ) k k ( Y )? If not, is there a way to relate k ( X × Y ) with k ( X ), and k ( Y )?

Answer & Explanation

Alessandro Schmidt

Alessandro Schmidt

Beginner2022-05-27Added 6 answers

I just thought I would expand on Alex's answer a bit. First I want to make sure we're assuming that k = k ¯ . Then we can always think of k ( X ) k k ( Y ) as a subset of k ( X × Y ) by the map extending ϕ ψ ϕ ψ (see note below), but you can see that in this way, k ( X ) k k ( Y ) only contains rational functions f ( x , y ) / g ( x , y ) k ( X × Y ) where g ( x , y ) is a product g 1 ( x ) g 2 ( y ) of polynomials in just x and y separately, and this is not all possible rational functions -- e.g. 1 x y 1 for X = Y = A k 1 . Of course, you may write k ( X × Y ) frac ( k ( X ) k k ( Y ) ) frac ( k [ X ] k k [ Y ] ), or you may just localize k ( X ) k k ( Y ) at the set of polynomials which are not of the above form, but these are probably not super helpful.
Note. It is non-trivial that, when k = k ¯ and A,B are k-algebras and also domains, then A k B is a domain. It is not always true when k k ¯ .

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