Noncircular construction of e and ln for the real line Could anyone direct me to (or poss

hushjelpw4

hushjelpw4

Answered question

2022-05-28

Noncircular construction of e and ln for the real line
Could anyone direct me to (or possibly detail) a construction of e and ln along the reals?
For example, they can define e = lim n ( 1 + 1 n ) n but from this definition how do they prove:
It converges!
d d x e x = e x
etc.!
Then if we know e x injective from R R + , we can call ln ( x ) the inverse of it. If we can prove ln is differentiable on its domain, then we can say:
1 = d d x x = d d x e ln ( x ) = e ln ( x ) ln ( x ) = x ln ( x ) ln ( x ) = x 1
but this all depends on the above.

Answer & Explanation

Norah Baxter

Norah Baxter

Beginner2022-05-29Added 10 answers

There are many possible paths through the exposition graph.
select a definition one or both of e x and log x for real x
select a definition of e prove all standard compatibilities between these definitions (such as e = exp ( 1 ) = log 1 ( 1 ) = lim ( 1 + 1 x ) x = 1 n ! ), equivalence to other standard definitions, and basic properties of the functions such as functional equations and power series developments.
Almost every book on real analysis, or on "rigorous calculus" (Spivak, Apostol or similar), and many ordinary calculus books that do not claim complete rigor but achieve it in this part of the exposition, will choose at least one path through the maze that accomplishes what you want.
skottyrottenmf

skottyrottenmf

Beginner2022-05-30Added 2 answers

We can define l n ( x ) = 1 x d t t and define e x as its inverse.
However, even the apprach you suggested works. Showing that the above sequence converges is not very hard. You can show that the sequence is increasing.
Also, you can show that the "power series" for e x converges absolutely.

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