Solve: 1 2 </mfrac> log <mrow class="MJX-TeXAtom-ORD">

misurrosne

misurrosne

Answered question

2022-06-22

Solve: 1 2 log 1 2 ( x 1 ) > log 1 2 ( 1 2 x 3 )
My try: Conditions identify: { x 1 > 0 1 2 x 3 > 0 { x > 1 2 x 3 < 1 x > 1
1 2 log 1 2 ( x 1 ) > log 1 2 ( 1 2 x 3 ) log 1 2 x 1 > log 1 2 ( 1 2 x 3 ) x 1 1 + 2 x 3 < 0
I don't know how to solve this Any equation: x 1 1 + 2 x 3 < 0 , please help me solve that into the result, please guide me, thanks.

Answer & Explanation

Ethen Valentine

Ethen Valentine

Beginner2022-06-23Added 15 answers

Ok, let me give you a hint.
1 2 log 1 2 ( x 1 ) > log 1 2 ( 1 2 x 3 )
So
log 1 2 ( x 1 ) > 2 log 1 2 ( 1 2 x 3 )
log 1 2 ( x 1 ) > log 1 2 [ ( 1 2 x 3 ) ] 2
( x 1 ) < [ ( 1 2 x 3 ) ] 2
( x 1 ) < ( 1 2 ( 2 x ) 1 3 + ( 2 x ) 2 3 )
0 < ( ( 2 x ) 2 ( 2 x ) 1 3 + ( 2 x ) 2 3 )
0 < ( ( 2 x ) 3 3 2 ( 2 x ) 1 3 + ( 2 x ) 2 3 )

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?