Solution for this Logarithmic Equation Recently I was going through a problem from the book Problems in Mathematics - *V Govorov & P Dybov* . (x-2)^(log^2(x-2)+log(x-2)^5-12)=10^2log(x-2) I tried solving by first considering log(x−2) as a variable, say t. Then I expressed (x−2) as 10^t . Then after using some properties of log, I reached till here- 10^(t^3+5t^2-12t)=10^2t or 10^(t^3+5t^2-12t-2)=t Now I have no idea how to approach further. The answer in the references says x=3,102,2+10^(−7)

$\frac{20b}{{\left(4b^3\right)}^3}$

Which operation could we perform in order to find the number of milliseconds in a year??
${\displaystyle 60\cdot 60\cdot 24\cdot 7\cdot 365}$
${\displaystyle 1000\cdot 60\cdot 60\cdot 24\cdot 365}$
${\displaystyle 24\cdot 60\cdot 100\cdot 7\cdot 52}$
${\displaystyle 1000\cdot 60\cdot 24\cdot 7\cdot 52?}$

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A) No
B) 0
C) Yes
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149600000000 is equal to
A)$1.496\times <!--\; \times \; -->{10}^{11}$
B)$1.496\times <!--\; \times \; -->{10}^{10}$
C)$1.496\times <!--\; \times \; -->{10}^{12}$
D)$1.496\times <!--\; \times \; -->{10}^8$

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