How I could show that :log1=0? I would be like somone to show me or give me a prove for this : Why ln1=0 ? Note that ln is logarithme népérien, the natural logarithm of a number is its logarithm to the base e. Thanks for any replies or any comments!

Parker Bird

Parker Bird

Answered question

2022-07-22

How I could show that : log 1 = 0?
I would be like somone to show me or give me a prove for this :
Why ln 1 = 0?
Note that ln is logarithme népérien, the natural logarithm of a number is its logarithm to the base e.
Thanks for any replies or any comments!

Answer & Explanation

Lillianna Mendoza

Lillianna Mendoza

Beginner2022-07-23Added 16 answers

log 1 = log ( 1 1 ) = log 1 + log 1 So  log 1 = log 1 + log 1 log 1 = log 1 0 = log 1
Markus Petty

Markus Petty

Beginner2022-07-24Added 2 answers

I will denote the natural logarithm of x by ln x
There are several definitions of the natural logarithm, so I will look at two of them.
1) ln ( ) : ( 0 , ) R is the inverse of the exponential function e : R ( 0 , ), where ( 0 , ) denotes the set of positive real numbers. Then because a 0 = 1 for every real number a, particularly e, it follows that ln ( 1 ) = 0
2) ln x = 1 x d t t . Then Evaluating at 1 gives ln 1 = 1 1 d x x = 0

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?