Write the equation of a line perpendicular to 6x-5y=-3 that passes through the point (-6,3)

Nash Frank

Nash Frank

Answered question

2022-07-26

Write the equation of a line perpendicular to 6x-5y=-3 that passes through the point (-6,3)

Answer & Explanation

sweetwisdomgw

sweetwisdomgw

Beginner2022-07-27Added 20 answers

Given that
6 x 5 y = 3
First we have to convert this line in slope intercept form y = mx + b for finding slope
5 y = 3 6 x 5 y = 3 + 6 x 5 y = 6 x + 3 y = 6 x + 3 5 y = ( 6 5 ) x + ( 3 5 )
m 1 m 2 = 1 ( 6 5 ) m 2 = 1 m 2 = 1 ( 5 6 ) m 2 = 5 6
Slope of second line m 2 = 5 6
y = m x + b y = ( 5 6 ) x + b
Substitute (-6,3 ) for finding b
3 = ( 5 6 ) ( 6 ) + b 3 = 5 + b 3 5 = b b = 2
Hence ,
The equation of line is ,
y = m x + b y = ( 5 6 ) x + ( 2 ) y = ( 5 6 ) x 2
Therefore ,
The equation of line is , y = ( 5 6 ) x 2

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