Israel Hale

2022-07-28

$\frac{3}{2y}\ufeff-\frac{3}{2y+4}=$

phravincegrln2

Beginner2022-07-29Added 19 answers

$\frac{3}{2y}\ufeff-\frac{3}{2y+4}=\frac{6y+12-6y}{2y(2y+4)}=\frac{12}{2y(2y+4)}=\frac{6}{y(2y+4)}=\frac{3}{{y}^{2}+2y}$

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