Damien Horton

2022-07-28

If the $\mathrm{log}(x)=-7.65$, how do you find x?

Shelby Strong

Beginner2022-07-29Added 9 answers

remember: $\mathrm{log}(x)$ means ${\mathrm{log}}_{10}(x)$

log property: ${a}^{{\mathrm{log}}_{10}(x)}=x$

${\mathrm{log}}_{10}(x)=-7.65$

${10}^{{\mathrm{log}}_{10}(x)}={10}^{-7.65}$

$x={10}^{-7.65}$

x=0.000000023872 or $2.23872\times {10}^{-8}$

log property: ${a}^{{\mathrm{log}}_{10}(x)}=x$

${\mathrm{log}}_{10}(x)=-7.65$

${10}^{{\mathrm{log}}_{10}(x)}={10}^{-7.65}$

$x={10}^{-7.65}$

x=0.000000023872 or $2.23872\times {10}^{-8}$

Makena Preston

Beginner2022-07-30Added 3 answers

$1.\mathrm{log}(x)=-7.65$

$2.{10}^{\mathrm{log}(x)}={10}^{-7.65}$ ---> when 10 to the powerof log, log and 10 cancel each other.

$3.X={10}^{-7.65}$

$2.{10}^{\mathrm{log}(x)}={10}^{-7.65}$ ---> when 10 to the powerof log, log and 10 cancel each other.

$3.X={10}^{-7.65}$

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