Solve the equation on the interval [0,2pi] sin 4x=(sqrt(3))/(2)

Leila Jennings

Leila Jennings

Answered question

2022-07-27

Solve the equation on the interval [ 0 , 2 π ]
sin 4 x = 3 2

Answer & Explanation

Lillianna Mendoza

Lillianna Mendoza

Beginner2022-07-28Added 16 answers

sin 4 x = 3 2
let ϕ = 4 x
sin ϕ = 3 2
ϕ = π 3 , 2 π 3
ϕ = 4 x = π 3 , 2 π 3
x = π 12 , π 6
termegolz6

termegolz6

Beginner2022-07-29Added 3 answers

x = π 12 , 11 π 12 , 15 or 165 degree
times 4 = π 3 , 2 π 3 30 or 150 degree
sin ( 30 ) a n d sin ( 150 ) = 3 2
Therefore x = π 12 , 11 π 12

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