Taniya Burns

2022-07-27

A coffee house has 20 pounds of a coffee that sells for $4 perpound. How many pounds of coffee that sells for $8 a pound shouldbe mixed with 20 pounds of the $ 4 per pound cofee to obtain ablend that will sell for $5 per pound? How much of the $5 per poundcoffee will there be?

Dominique Ferrell

Beginner2022-07-28Added 18 answers

type 1 coffee: sells for $4 per pound

type 2 coffee: sells for $8 per pound

let x pounds of type 2 coffee is mixed with20 pounds of type 1 coffee to obtain a blend that will sell for $5 per pound.

selling price of type 1 coffee (20 pounds at a rate $4/pound) =20*4 = 80$

selling price of type 2 coffee (x pounds at a rate $8/pound) = x*8= 8x $

total coffee(type 1 + type 2) = (20 + x)pound if the blend sells for 5$ /pound then selling price = 5*(20 + x) =100 + 5x $

so we can say,

100 + 5x = 80 + 8x

$\Rightarrow 8x-5x=100-80=20$

$\Rightarrow 3x=20$

$\Rightarrow x=20/3=6.67$

Answer: 6.67 pound of type 2 coffee(that sells for $8 per pound)

type 2 coffee: sells for $8 per pound

let x pounds of type 2 coffee is mixed with20 pounds of type 1 coffee to obtain a blend that will sell for $5 per pound.

selling price of type 1 coffee (20 pounds at a rate $4/pound) =20*4 = 80$

selling price of type 2 coffee (x pounds at a rate $8/pound) = x*8= 8x $

total coffee(type 1 + type 2) = (20 + x)pound if the blend sells for 5$ /pound then selling price = 5*(20 + x) =100 + 5x $

so we can say,

100 + 5x = 80 + 8x

$\Rightarrow 8x-5x=100-80=20$

$\Rightarrow 3x=20$

$\Rightarrow x=20/3=6.67$

Answer: 6.67 pound of type 2 coffee(that sells for $8 per pound)

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