agantisbz

2022-07-27

Complete the square.

$5{x}^{2}+2x-10$

$5{x}^{2}+2x-10$

Hassan Watkins

Beginner2022-07-28Added 18 answers

$5{x}^{2}+2x-10$

Taking out 5 as common : $5({x}^{2}+(\frac{2}{5})x-2)\phantom{\rule{0ex}{0ex}}5({x}^{2}+(\frac{2}{5})x+4/25-4/25-2)\phantom{\rule{0ex}{0ex}}5[(x+\frac{2}{5}{)}^{2}-\frac{4+50}{25})\phantom{\rule{0ex}{0ex}}5[(x+\frac{2}{5}{)}^{2}-\frac{54}{25}]\phantom{\rule{0ex}{0ex}}5(x+\frac{2}{5}{)}^{2}-\frac{54}{5}$

Taking out 5 as common : $5({x}^{2}+(\frac{2}{5})x-2)\phantom{\rule{0ex}{0ex}}5({x}^{2}+(\frac{2}{5})x+4/25-4/25-2)\phantom{\rule{0ex}{0ex}}5[(x+\frac{2}{5}{)}^{2}-\frac{4+50}{25})\phantom{\rule{0ex}{0ex}}5[(x+\frac{2}{5}{)}^{2}-\frac{54}{25}]\phantom{\rule{0ex}{0ex}}5(x+\frac{2}{5}{)}^{2}-\frac{54}{5}$

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