1. solve the equation and check the solution 3/2(z+5) -1/4(z+24) = 0 2. 2 / (x-4)(x-2) = 1 / x-4 + 2/ x-2

Paxton Hoffman

Paxton Hoffman

Answered question

2022-07-30

1. solve the equation and check the solution 3/2(z+5) -1/4(z+24) = 0
2. 2 / (x-4)(x-2) = 1 / x-4 + 2/ x-2

Answer & Explanation

Tolamaes04

Tolamaes04

Beginner2022-07-31Added 12 answers

3/2(z+5) - 1/4(z+24) = 0
solve for Z:
3/2z+10 - 1/4z+96 = 0
3/2z+10 = 1/4z+96
3 = (2z+10)/(4z+96)
3 (4z+96) = (2z+10)
12z+288 = 2z+10
10z + 288 = 10
10z = -278
z = -27.8
Now, when you plug in the value of Z into the originalproblem you should get:
(-0.0658) - (-0.0658) = 0
2.
2 / (x-4)(x-2) = 1 / x-4 + 2/x-2
=> 2 / (x-4)(x-2) = [1*(x-2) +2*(x-4)] / (x-4)*( x-2).................doing LCM on right hand side
=> 2 / (x-4)(x-2) = [x - 2 + 2x- 8] / (x-4)*( x-2)
=> 2 / (x-4)(x-2) = [3x - 10] / (x-4)*( x-2)
hence either,
2 = 3x -10 or (x-4)*(x-2) = 0
=> 3x =12 or (x-4) = 0 or (x-2) = 0
=> x =12/3 or x = 4 or x = 2
= 4
Answer: x= 4;
x = 2;

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