Solve the following equation for x; ln(x)+ln(x−1)=0 What I did is the following but I'm pretty sure its wrong.. ln(x)+ln(x−1)=0 ln(x)=−ln(x−1) e^)ln(x))=e^(−ln(x−1))) x=−x−1 2x=−1 x=−1/2

Nica2t

Nica2t

Answered question

2022-08-12

Solve ln ( x ) + ln ( x 1 ) = 0 for x
Solve the following equation for x;
ln ( x ) + ln ( x 1 ) = 0
What I did is the following but I'm pretty sure its wrong..
ln ( x ) + ln ( x 1 ) = 0
ln ( x ) = ln ( x 1 )
e ln ( x ) = e ln ( x 1 ) )
x = x 1
2 x = 1
x = 1 2

Answer & Explanation

Ayla Coffey

Ayla Coffey

Beginner2022-08-13Added 8 answers

Hint
ln a + ln b = ln ( a b )
and
ln a = 0 a = 1

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?