I was going through some questions of Relations and Functions and now I am stuck to one. Question says Question: Domain of definition of the function f(x)=(9)/(9-x^2)+log_(10)(x^3-x) is? Till yet I know that the denominator of first term (i.e. (9)/(9-x^2) ) will be non-zero. So I figured, 9−x^2!=0 =>x!=+-3 And from second term (i.e. log_(10)x^3−x), we know that the term inside the logarithm can never be less than or equal to zero. So, log_(10)(x^3-x) =>x^3−x>0 => (x−1)x(x+1)>0 From here I know that if x−1 is negative when x<1 and positive when x>1. x+1 is negative when x<−1 and positive when x>−1. But I am still not getting the domain in a specific interval.I seriously need help in this. Thanks in advance

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