Trying to solve equation, used Quick math but don't know how it got the solution. Please help !! 28207=(76762-x^2)+(x-76831)^2

suffisantfn

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2022-08-25

Trying to solve equation, used Quick math but don't know how it got the solution. Please help !!
28207 = ( 76762 x 2 ) + ( x 76831 ) 2

Answer & Explanation

Pegoxv

Pegoxv

Beginner2022-08-26Added 7 answers

Expanding the problem:
28207 = ( 76762 x ) ( 76762 x ) + ( x 76831 ) ( x 76831 ) UseFOIL to multiply the binomial times binomials
28207 = ( 76762 2 76762 x 76762 x + x 2 ) + ( x 2 76831 x 76831 x + 76831 2 ) Now square the numbers and add like terms
28207 = 5 , 892 , 404 , 644 153 , 524 x + x 2 + x 2 153 , 662 x + 5 , 903 , 002 , 561 Add like terms in this line
28207 = 2 x 2 307 , 186 x + 11 , 795 , 407 , 205 Move 28207to the right side of the equation by subtracting it from bothsides
0 = 2 x 2 307 , 186 x + 11 , 795 , 378 , 798 Now divideevery term by two to make it a "simpler" problem
0 = x 2 153 , 593 x + 5 , 897 , 689 , 399
Let a = 1 , b = 153 , 593  and  c = 5 , 897 , 689 , 499
Now use a, b, and c to plug into the quadratic equation: x b ± b 2 4 a c 2 a
x = 153 , 593 ± ( 153 , 593 ) 2 4 ( 1 ) ( 5 , 897 , 689 , 499 ) 2 ( 1 )
Now simplify the information underthe radical
x = 153 , 593 ± ( 153 , 593 ) 2 4 ( 1 ) ( 5 , 897 , 689 , 399 ) 2 ( 1 )
x = 153 , 593 ± 51653 2 So these are the answers written inone radical but if you split it then you have the answer you haveabove.

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