Solve. 1/2 (6c+4)-2(c+ 5/2)= 2/3 (9-3c)

Felix Fitzgerald

Felix Fitzgerald

Open question

2022-09-01

Solve. 1/2 (6c+4)-2(c+ 5/2)= 2/3 (9-3c)

Answer & Explanation

Giovanni Salazar

Giovanni Salazar

Beginner2022-09-02Added 4 answers

I would distribute first, that is multiply the number in frontof the parantheses to both things inside.
That gives you:
3c + 2 - 2c - 5 = 6 - 2c
Combine like terms on left side
c - 3 = 6 - 2c
Bring c's to left, numbers to right
Add 2c to both sides, add 3 to both sides
3c = 9
Divide both sides by 3, you get
c = 3
ceriserasb6

ceriserasb6

Beginner2022-09-03Added 2 answers

1/2 (6c + 4) - 2 (c + 5/2) = 2/3 (9- 3c)
If the above is what you were trying to type,then the first thing to do is remove the parentheses using the distributive rule.
Applying the distributive rule, we get this:
3c + 2 - 2c - 5 = 6 - 2c
We now combine like terms.
c - 3 = 6 - 2c
Again, we combine liketerms.
c + 2c = 6 + 3
3c = 9
Divide both sides by 3.
c = 9/3
c = 3
How do we know that c = 3 is right?
We can plug 3 for c in the orginal equation given.
If we get the same answer on both sides of the equation, then we will know if c = 3 is right or wrong.
1/2 (6c+4)-2(c+ 5/2)= 2/3 (9-3c)....This is your original equation given.
(1/2)(6(3) + 4) - 2(3 + 5/2) = (2/3) (9 -3(3))....Replace c with 3 and simplify.
(1/2) (22) - 2(11/2) = (2/3)(0)
11 - 11 = 0
0 = 0...It checks!
We got the same answer of 0 = 0.
This is our prove that c = 3.

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