dyin2be0ey

2022-09-01

Solve.

1)${\mathrm{log}}_{6}\ufeff0.8$

2)${\mathrm{log}}_{1/2}32$

1)${\mathrm{log}}_{6}\ufeff0.8$

2)${\mathrm{log}}_{1/2}32$

Adam Bradley

Beginner2022-09-02Added 10 answers

$\mathrm{log}.8/\mathrm{log}6=-.125$

$\mathrm{log}32/\mathrm{log}1/2=-5.000$

$\mathrm{log}32/\mathrm{log}1/2=-5.000$

Patience Owens

Beginner2022-09-03Added 1 answers

$1)=-0124539$

$2)={\mathrm{log}}_{2}^{-1}{2}^{5}=\frac{5}{-1}{\mathrm{log}}_{2}2=-5$

$2)={\mathrm{log}}_{2}^{-1}{2}^{5}=\frac{5}{-1}{\mathrm{log}}_{2}2=-5$

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