rectangle H=x+2 W= x+1 triangle x+2; x+9; x+7 Solve for X so that the perimiters are the same for the triangle and the rectangle

Bellenik3

Bellenik3

Answered question

2022-09-03

rectangle H=x+2 W= x+1
triangle x+2; x+9; x+7
Solve for X so that the perimiters are the same for the triangle and the rectangle

Answer & Explanation

lywyk0

lywyk0

Beginner2022-09-04Added 12 answers

If H stands for height and W stands for width then theperimeter of the rectangle is 2H +2W which means:
Perimeter of Rectangle = Perimeter of Triangle
2(x+2)+2(x+1) = (x+2)+(x+9)+(x+7)
4x+6=3x+18
x=12
Felix Fitzgerald

Felix Fitzgerald

Beginner2022-09-05Added 2 answers

perimeter of rectangle =perimeter of triangle
2(x+2 +x+1 ) =x+7 +x+2 +x+9
2(2x+3) =3x +18
4x +6 =3x +18
x=12

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