Twice the number of reds exceeds three times the number ofblues by 8. The ratio of the number of reds to the sum of thenumber of reds to the number of blues was 5 to 7. How many were redand how many were blue?

Arnav Heath

Arnav Heath

Answered question

2022-09-04

Twice the number of reds exceeds three times the number ofblues by 8. The ratio of the number of reds to the sum of thenumber of reds to the number of blues was 5 to 7. How many were redand how many were blue?

Answer & Explanation

etapi9a

etapi9a

Beginner2022-09-05Added 12 answers

let r be number of reds, and b be the number of blues
2r-3b = 8 .................(1)
r r + b = 5 7 ..............(2)
from (2) 7r = 5r + 5b
2r= 5b
r = 5 b 2 substitute this into (1)
2 ( 5 b 2 ) 3 b = 8
2 b = 8 , b = 4
r = 20/2 = 10
there are 4 blues and 10 reds

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