Find the smaller of the two real solutions of thisequation: 2x2 + 5x = 12 are two realnumbers. The sum of these two real numbers is: A. -4 B.-2 C.-1.5 D.1.5 E.4 An equivalent form of 2/x + 1 - 3/5 is: (where x-1) A. -3x + 13/5x +5 B. -3x + 11/5x + 5 C. -3x + 7/5x+ 1 D.-3x + 7/ 5x + 5 E. -3x+ 13/5x +1

equipokypip1

equipokypip1

Answered question

2022-09-02

Find the smaller of the two real solutions of thisequation: 2x2 + 5x = 12 are two realnumbers. The sum of these two real numbers is:
A. -4 B.-2 C.-1.5 D.1.5 E.4
An equivalent form of 2/x + 1 - 3/5 is: (where x-1)
A. -3x + 13/5x +5
B. -3x + 11/5x + 5
C. -3x + 7/5x+ 1
D.-3x + 7/ 5x + 5
E. -3x+ 13/5x +1

Answer & Explanation

adwelirlz

adwelirlz

Beginner2022-09-03Added 10 answers

2 x 2 + 5 x = 12 2 x 2 + 5 x 12 = 0 ( 2 x 3 ) ( x + 4 ) = 0 2 x 3 = 0 2 x = 0 ( 3 ) 2 x = 0 + 3 2 x = 3 x = 3 / 2 x + 4 = 0 x = 0 4 x = 4 A 2 x + 1 3 5 let's substitute  2  to  x 2 / 2 + 1 3 5 1 + 1 3 5 2 3 5 10 / 5 3 5 7 / 5

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