Members of the Ski Club contributed equally to obtain $1800for a holiday trip. When 6 members found that they could not go,their contributions were refunded and each remaining member thenhad to pay $10 more to raise the $1800. How many went on the trip?

potrefilizx

potrefilizx

Answered question

2022-09-03

Members of the Ski Club contributed equally to obtain $1800for a holiday trip. When 6 members found that they could not go,their contributions were refunded and each remaining member thenhad to pay $10 more to raise the $1800. How many went on the trip?

Answer & Explanation

Yadira Mcdowell

Yadira Mcdowell

Beginner2022-09-04Added 13 answers

x is the original number of students, y is original the price
xy = 1800
(x - 6)(y+10) = 1800 = xy
xy + 10x - 6y - 60 = xy
Substitute and 10x = 60 - 6y
Plug (60 - 6y)/10 into the original equation for x
6 y 0.6 y 2 = 1800
Solving for y you get $50
50x = 1800
x = 36 original members
6 dropped out so 30 went.
iescabroussexg

iescabroussexg

Beginner2022-09-05Added 4 answers

Let x=number of students originally going on the trip.
p=how much each student had to originally pay.
So: p*x = 1800 originally and
(p+10)(x-6)=1800 after 6 students dropped out and each had to pay10 more.
Solve these two equations:
p = 1800/x
Substituting into the second equation:
(1800/x + 10)(x-6)=1800
=> 1800+10x-10800/x -60 = 1800
=> 10x-10800/x = 60
=> x-1080/x = 6 Multiply all sides by x
=> x 2 1080 = 6 x
=> x 2 6 x 1080 = 0
Solve using quadratic equation:
x = ( 6 + / 36 + 4320 ) / 2 = 36 or -30. -30 doesn't make sense sowe throw it out, so originally 36 people were going on thetrip,
now there are 30 people going.

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